Question

A Review Part C Learning Goal: To use the principle of linear impulse and momentum to relate a force on an object to the resulting velocity of the object at different times. The equation of motion for a particle of mass m can be written as dv ΣF - = ma By rearranging the terms and integrating, this equation becomes the principle of linear impulse and momentum =ma A stop block, s prevents a crate from sliding down a 0 = 39 0 incline. (Figure 1) A tensile force F= (Fot) N acts on the crate parallel to the incline, where Fo = 250 N/s. If the coefficients of static and kinetic friction between the crate and the incline are ha = 0.295 and the = 0.240, respectively, and the crate has a mass of 52.6 kg, how long will it take until the crate reaches a velocity of 3.62 m/s as it moves up the incline? Express your answer numerically in seconds to three significant figures. View Available Hint(s) m - Mvi For problem-solving purposes, this principle is often rewritten as Figure < 1 of 1 90 AED 11 F SI vec PI Ch Submit Request Answer Fin Provide Feedback Next > Сог

Answer 1

Solh =) will be solved in This question two parts. (1). When Static friction is acting - 516 TA390 516 Singo 324.73N 4014 te 118.295 = 40N 52.6 X 9.81N = 5 16N Now Static time friction will act upto the is in rest. when body = 324.73 +118.295 F = 443.025

D 250 x + = 4 43.025 + 1.772) sec upto 1.7721 seconds body will be in rest lii). When body is in motion 250+ 40 IX Hin K 96.24N TON 324.73 390 Wea will apply ff.dt f. dt = M(V2 -V.) from for time 1.7721 to t seconds. rest initially ) V = 0 12 = 3.62 mis in= 52.6kg