Question

Write a program to Read and parse the “Nov ” lines and pull out the event message from the line. Count the number of messages from "kernel" using a dictionary.

After all the data has been read, print the date with the most occurrence by creating a list of (count, date) tuples from the dictionary and then sorting the list in reverse order and print out the date which has the most occurrence.

Answer 1

Solution:-

Code to copy:-

kernel_count = {"kernel":0} #Dictionary for kernal count

date_count = {} #Dictionary for date count

with open ("messages.2","r") as f: #OPen file

for line in f:

if line.strip().split()[0] == "Nov": #Parse lines starting with Nov

try:

if line.strip().split()[4] == "kernel:": #Check for message from kernel

kernel_count['kernel'] +=1 #Update dict

except:

continue

date = line.strip().split()[1] #get date from line

date_count[date] = date_count.get(date, 0) + 1 #update dict counter

li = [(x,y) for x,y in date_count.items()] #Convert dict to list

s_li = sorted(li, key = lambda x: x[1], reverse=True) #Sort in decending order

print(s_li)

print("Number of messages from 'kernal':",kernel_count['kernel'])

print("Most occuring date:",s_li[0][0])

Screen shot:-

kernel_count = {"kernel":0} #Dictionary for kernal count date_count = {} #Dictionary for date count 3 with open ("messages.2","1") as f: #Open file 4 for line in f: 5 if line.strip().split( [0] == "Nov": #Parse lines starting with Nov try: if line.strip().split([4] "kernel:": #Check for message from kernel 8 A kernel_count['kernel'] +=1 #Update dict except: 10 A continue 11 date = line.strip().split([1] #get date from line 12 date_count[date] = date_count.get(date, 0 + 1 #update dict counter 13 14 li = [(x,y) for x,y in date_count.items()] #Convert dict to list 15 s_li = sorted(li, key = lambda x: x[1], reverse=True) #Sort in decending order 16 print(s_li) 17 print("Number of messages from 'kernal':', kernel_count['kernel']) 18 print("Most occuring date:",s_li[0][0]) CN NOON NA

Output:-

Number of messages from 'kernal' 70 Most occuring date: 7

Thanking you.