Question

A magnetic field passes through a stationary wire loop, and its magnitude changes in time according to the graph in the drawing. The direction of the field remains constant, however. There are three equal time intervals indicated in the graph: 0 - 3.0 s, 3.0 - 6.0 s, and 6.0 - 9.0 s. The loop consists of 55 turns of wire and has an area of 0.15 m2. The magnetic field is oriented parallel to the normal to the loop. For purposes of this problem, this means that o = 0º in Equation 22.2. (a) For each interval, determine the induced emf. (b) The wire has a resistance of 0.50 12. Determine the induced current for the first and third intervals. 0.40 B (T) 0.20 OM 1 (s) 3.0 6.0 9.0 (a) 1 = €2 = E3 = (b) 11 10 13 =

Answer 1

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We know that ~ 2,2 Induce Emf e=-do dt 3.0 60 9.9145) (PA) BAGO) ge= - Ada here bz6 => Coso =) for Ist interval &-- For N-turns e=-NA dB at given A=0e1sm? N=55 turns R=0.52 of for Ist interval &=-ss ss (0.15) / 0.4-0 - lol v 3.0 for Ind. Interval 0.4-0.4 cov - 3 interval 0.2-0.41 0.55 V - g-6 We know that ca 2-55(0-15) ( for Tod E3= 6 Ia VEEEER for Ist I, = E El R - Flol Amp = -2.2 Amp for litro Iz = E Ez R oss Amp=lol Amp