Question

1. Hours (H) refers to the number of hours preparing for the course per week. Existing literature shows that there is a positive relationship between GPA and Hours. Provide Reference.
2. Days of practice refers to the average number of days spent per week training instead of studying per week. Literature shows that DPA days can be negatively related. Offer reference(s)
3. Others

Student-Athletes	GPA	Days of Practice (1X) WKLY	Hours of Study (2X) WKLY
1	3.2	5	10
2	3.0	5	8.5
3	2.8	6	4.5
4	3.0	5	6
5	2.7	5	3
6	3.6	5	10
7	3.3	5	8
8	2.8	6	3
9	3.0	6	7.5
10	3.4	5	7
11	3.1	5	8
12	3.1	5	6

Answer 1

a.

3.5 3 2.5 GPA 2 1.5 015 0 @ 2 6 B 10 Hours

х Y X*Y X2 y2 10 3.2 32 100 10.24 8.5 3 25.5 72.25 9 4.5 2.8 12.6 20.25 7.84 6 3 18 36 9 3 2.7 8.1 9 7.29 10 3.6 36 100 12.96 8 3.3 26.4 64 10.89 3 2.8 8.4 9 7.84 7 3 21 19 9 7 3.4 23.8 49 11.56 8.5 3.1 26.35 72.25 9.61 6 3.1 18.6 36 9.61 Sum = 81.5 37 256.75 616.75 114.84 The correlation coefficient r is computed using the following expression: r = SSXY SSXX SSyy where 1 SSXY 3x + (2x) (2) ==$^-+ (8 x) SSxx = 2 n n 1 SSyy = n i=1 i=1 In this case, based on the data provided, we get that 1 SSXY = 256.75 – (81.5 x 37) = 5.458 12 1 SSxx = 616.75 1 (81.5)2 = 63.229 12 (37) = 0.757 1 S Syy = 114.84 - 12 Therefore, based on this information, the sample correlation coefficient is computed as follows 5.458 r = SSXY VSSXX SSYY = 0.789 63.229 X 0.757
thus it can be interpreted as there is positive relationship between GPA and hours of study per week.

b.

3.5 3 2.5 GPA 2 1.5 1 0.5 4.8 ח 5.2 5.4 5.6 5.B 6 OPA

х Y X*Y X2 y2 5 3.2 16 25 10.24 5 3 15 25 9 6 2.8 16.8 36 7.84 5 3 15 25 9 5 2.7 13.5 25 7.29 5 3.6 18 25 12.96 5 3.3 16.5 25 10.89 6 2.8 16.8 36 7.84 6 3 18 36 9 5 3.4 17 25 11.56 5 3.1 15.5 25 9.61 5 3.1 15.5 25 9.61 Sum = 63 37 193.6 333 114.84 The correlation coefficient r is computed using the following expression: r SSXY VSSXX SSyy where 1 SSxy = x;y; 2 1 SSxx = = $xx-+($) ") 3x : (22) 37-: (m) SSyy = y In this case, based on the data provided, we get that 1 SSXY = 193.6 – (63 x 37) = -0.65 12 1 SSxx 333 12 (63)2 = 2.25 1 S Syy = 114.84 - (37)2 = 0.757 12 Therefore, based on this information, the sample correlation coefficient is computed as follows r = SSXY SSXX SSyy -0.65 2.25 x 0.757 -0.498 V

Thus it can be interpreted as ther is negative relationship between GPA and days of practice per week.

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