A container contains 35 green tokens, 5 blue tokens, and 4 red tokens. Two tokens are randomly selected without replacement Compute P(FIE).
E - you select a non-red token first
F - the second token is red
according to given question we have to find conditional probability of token is red given that first selected token is non red.
4 tokens are red and 40 tokens are non red
p(F) = 4/43 , because after selecting 1st token there are only 43 token left.
p(E) = 40/44
now conditional probability from Baye's theorem can be find out as follows
p(
) /p(E)
4/43
0.093
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A container contains 35 green tokens, 5 blue tokens, and 4 red tokens
A container contains 30 green tokens, 15 blue tokens, and 3 red tokens. Two tokens are randomly selected without replacement. Compute P(F|E).E−you select a blue token firstF−the second token is blue
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