Question

Suppose the mean income of firms in the industry for a year is 85 million dollars with a standard deviation of 5 million dollars. If incomes for the industry are distributed normally, what is the probability that a randomly selected firm will earn more than 80 million dollars? Round your answer to four decimal places. Answer 2 Points Tables Keypad If you would like to look up the value in a table, select the table you want to view, then either click the cell at the intersection of the row and column or use the arrow keys to find the appropriate cell in the table and select it using the Space key. Normal Table -o to - Normal Table -o to z

Answer 1

Solution :

Given that ,

P(x > 80) = 1 - p( x< 80 )

=1- p P[(x - $\mu$) / $\sigma$ < (80 - 85) / 5]

=1- P(z < -1.00)

= 1 - 0.1587

= 0.8413