Question

Scenario: Karen is tasked with caring for Remington, a 6 month old Rottweiler mix weighing 27...

Scenario:

Karen is tasked with caring for Remington, a 6 month old Rottweiler mix weighing 27 lbs. Remington was diagnosed with parvovirus and was admitted to the isolation ward today. He is having large amounts of vomiting and diarrhea. Karen must help the veterinarian keep Remington hydrated by correctly calculating his fluid needs.

  1. The veterinarian directs Karen to start Remington on a bland diet. She wants to begin by feeding only 30% of Remington’s resting energy requirement (RER) for the day. Karen plans to split this total over 3 meals.

The RER formula is: 30 kcal/kg X body weight (in kg) + 70 kcal.

  1. Calculate Remington’s RER. (2 points)
  2. How many calories per day will Remington receive according to the diet specifications? (2 points)
  3. Calculate the number of calories per meal. (2 points)
  1. Karen chooses Hill’s canned a/d diet for Remington. Each 5.5 oz can contains 183 kcal. Based on your previous calculation:
    1. How many cans of food will Remington need at each meal? (2 points)
    2. How many cans will he require each day? (2 points)

6. At the end of Karen’s shift, the veterinarian performs a physical on Remington and decides that he is not adequately fluid resuscitated. What actions might the veterinarian take? What are the consequences if Remington is not fluid resuscitated? Use at least three sentences to answer the question. (4 points)

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Answer #1

a.

RER= 30kcal/kg × body weight (kg) +70

Now, weight = 27 lbs = 27/2.2 = 12.27 kg

So, RER= (30× 12.27 ) +70= 368.1+70=438.1 Kcal.

b. According to diet specification he is given only 30% of RER .

SO, calories per day = 438.1× 30% = 438.1× 30/100 = 131.43 kcal.

C.

Total diet is spilted in 3 meals.

So, number of calories per meal= number of calories in the day diet specification / 3 = 131.43/ 3 = 43.8 kcal.

a.

Each meal is consist of 43.8 kcal.

Each can contain 183 kcal .

So, 183 kcal of energy is present in 1 can

1 kcal of energy is present in 1/183 can

43.8 kcal of energy is present in (1/183)× 43.8 = 0.239 can

Answer: 0.239 can

b.

Each day energy is recieved according to diet = 131.43 kcal.

So, 183 kcal of energy come from 1 can

1 kcal of energy come from 1/183 can

So, 131.43 kcal comes from (1/183)× 131.43 = 0.718 can

Answer : 0.718 can

6. Action taken by Veterinarian --

As Remington has diagnosed with parvovirus infection so oral route of fluid resuscitation is not recommended. Subcutaneous route of fluid resuscitation is the most wellknown route. Also intravenous route administration can be given depending upon the percentage of dehydration. The dehydration is measured by, first, calculate the fluid deficit amount by using formula- body weight in kg× percentage of dehydration in decimal . Secondly, fluid loses is estimated. Thirdly, according to the formula 50 ml /kg/day the amount fluid which is resuscitated is to be calculated.

Consequence if Remington is not fluid resuscitated----

As already he has a large amount of vomiting and diarrhoea so fluid resuscitation is important and there is absolute indication because the infection is due to parvovirus. If the fluid resuscitation is not done then , the dehydration is will be further means more than 10% it can result loss of skin moisture, sticking mucouse membranes, corneal dullness and slow response of cornea, weak pulse , tachycardia. If the dehydration level is more than 12% shock can occur, consciousness alternation can be there and ultimately uf it is more than 15% then it can leads to death also.

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