For a galvanic cell using the reaction Cu2+ (aq) + Sn2+ (aq) Cu (s) + Sn4+ (aq), calculate the cell potential at 25°C when [Cu2+] = 2.5 × 10-3 M, [Sn2+] = 2.5 × 10-4 M and [Sn4+] = 3.5 × 10-3 M
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For a galvanic cell using the reaction Cu2+ (aq) + Sn2+ (aq) Cu (s) + Sn4+ (aq),...
Consider a galvanic cell that uses the reaction Cu(s) + 2Fe3+(aq) → Cu2+(aq) + 2Fe2+(aq) What is the potential of a cell at 25 °C that has the following ion concentrations? [Fe3+] = 1.0 x 10-4 M [Cu2+] = 0.25 M [Fe2+] = 0.20 M
Consider a galvanic cell that uses the reaction Cu (s) + 2Fe+ (aq) Cu2+ (aq) + 2Fe+ (aq) Part A What is the potential of a cell at 25 C that has the following ion concentrations? Fel 1 - 1.5x10-4M. Cu2+1 -0.29 M. Fe2+1 -0.18 M Express your answer to two significant figures and include the appropriate units. HA ? Value Units Submit Resvest Answer A galvanie cel has an iron electrode in contact with 0.19 M FeSO, and a...
Conceptual: Consider a Sn(s)|Sn2+(aq) || Cu2+(aq)|Cu(s) cell. If the Sn2+ concentration is increased, what will happen to the measured Ecell value? • Calculation, full-reaction Nernst equation: Use the full Nernst equation to calculate Ecell for the conditions described… • Easier: Ni | Ni2+(0.300 M) || Cu2+(0.002 M) | Cu • Harder: Al | Al3+(0.002 M) || Cu2+(4.00 M) | Cu • Calculation, half-reaction Nernst equation: Use the Nernst equation to calculate E at pH 3.00 and [Cl- ] = 0.0035...
A concentration cell is set up using the following reaction: Sn4+ (aq) + 2e – Sn2+ (aq) ° = 0.150 V The standard line notation, including initial concentrations, for this cell is shown below: (Please note that concentration of ions shown in the anode compartment are in the same order as in the cathode compartment.) Pt (s)[Sn4+] (0.645 M), [Sn2+ ](1.39 M) || (Sn4+] (1.37 M), [Sn2+] (0.611 M) |Pt (s) The initial potential of this concentration cell, at 298...
calculate the cell potential of this reaction. Cu|Cu2+ (0.0100M)||Cu2+ (0.1M)|Cu . The half-cell reaction is Cu2+(aq) + 2e- --> Cu(s) with standard potential Eo is 0.3419V
A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction: Cu2+(aq) + Zn(s) --> +Cu(s) + Zn2+(aq) Suppose the cell is prepared with 5.20 M Cu2+ in one half-cell and 3.49 M Zn2+ in the other. Calculate the cell voltage under these conditions. Round your answer to 3 significant digits.
Calculate the cell potential for the galvanic cell in which the given reaction occurs at 25 °C, given that [Sn2+]=0.0622 M[Sn2+]=0.0622 M, [Co3+]=0.0428 M[Co3+]=0.0428 M, [Sn4+]=0.00221 M[Sn4+]=0.00221 M, and [Co2+]=0.01111 M[Co2+]=0.01111 M. Standard reduction potentials can be found in this table. Sn2+(aq)+2Co3+(aq)↽−−⇀ Sn4+(aq)+2Co2+(aq)
A galvanic cell based on the following reactions Cu 2+ (aq) + 2e- + Cu(s) E°=0.339 V (AD + 14H(aq) + 6e-4 2Cr 3+(aq) + 7 H2O(1) Eo=1.330 V a) Write the overall cell reaction and determine its voltage. b) If the E value of the galvanic cell is 1.2 le of the galvanic cell is 1.254 V, calculate the pH of the cell when [Cu2+]=0.00010 M, Cr-0,2-1=0.00460 M, Cr3+1=1.0x102 M. The Nerst equation is E=E - (0.0592/n)logQ
Calculate the cell potential for the galvanic cell in which the given reaction occurs at 25 °C, given that [Sn2+]=0.0607 M, [Co3+]=0.0428 M, [Sn4+]=0.00554 M, and [Co2+]=0.01109 M. Standard reduction potentials can be found in this table. Sn2+(aq)+2Co3+(aq)−⇀↽− Sn4+(aq)+2Co2+(aq) E= V
A galvanic cell Cr(s)|Cr2+(aq) || Cu2+(aq)|Cu(s) is constructed using a completely immersed Cr electrode that weighs 35.4 g and a Cu electrode immersed in 462 mL of 1.00 M Cu2+(aq) solution. A steady current of 0.0795 A is drawn from the cell as the electrons move from the Cr electrode to the Cu electrode. (a) Which reactant is the limiting reactant in this cell? Enter symbol (b) How long does it take for the cell to be completely discharged? s...