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QUESTION 23 - For the reaction below at 298 K: 4NO (9) N20 (9) + N203...
For the reaction below at 298 K: 4NO (g) → N2O (g) + N2O3 (g) ∆H = -192.7 kJ and ∆S = -308.2 J/K Which of the following statements is TRUE? ∆G > 0 at 298K At higher temperatures, the reaction will be spontaneous At lower temperatures, the reaction will be spontaneous The reaction is spontaneous at all temperatures. None of the above are true.
What is ∆So at 298 K for the following reaction? 2 H2S(g) + 3 O2(g) → 2 SO2(g) + 2 H2O(g) ΔH°f (kJ/mol) -20.6 -296.8 -241.8 Δ G°f( kJ/mol) -33 -300.2 -228.60
1.) Calculate ΔHºrxn ΔSsurr and ΔSºrxn to determine if the reaction is spontaneous at 298 K ΔHºf : PCl3(g) = -287 kj/mol ΔSºf : PCl3(g) = -3112 J/mol *K ΔSºf : P4(s) = 41.1 J/mol*K ΔSºf : Cl2(g)= 2230 J/mol *K P4(s) +6Cl2(g) ------> 4PCl3(g) 2.) Calculate ΔGºrxn from enthalpy and entropy values at 298 K 4NH3 (g) +5O2(g) -----> 4 NO(g) +6H2O(g) ΔHºf : NO(g) = 90.29 kj/mol ΔHºf: H2O(g) = -241.826 kJ/mol ΔHºf: NH3(g) = -45.9 kJ/mol ΔSºf : NO(g)...
QUESTION Use the given data at 298 K to calculate AGº for the reaction 2012(g) + SO2(g) → SOC12(g) + Cl20(g) Substance: Cl2 (8) SO2(8) SOCI2(g) Cl20(g) AHºf (kJ/mol): 0 -296.8 -212.5 80.3 Sº (J/mol-K): 223.0 248.1 309.77 266.1 O 129.3 kJ 133.6 k) 196.0 k) 199.8 k) 229.6 kJ
Enter your numbers into 1 decimal places. For the reaction:
4NO(g) + 6H2O(g) ⇋ 4NH3(g) +
5O2(g)
Determine ΔH° and ΔS° for the reaction at 298
K.
ΔH0(kJ)
ΔS0(J/K)
Assuming that these values are relatively independent of
temperature, calculate ΔG° at 100.°C and 2560.°C.
ΔG0(kJ)at
100℃
ΔG0(kJ)
at 2560℃
3. Is this reaction spontaneous at all range of temperature?
Enter 1 for true or 0 for false.
4. Calculate the K at 298K for the above
reaction. Enter "is" for...
For the reaction at 298 K, CH4 9 + 2029 + CO2 9 + 2H20 g the values of AH° and ASº are -803 kJ and -4.00 J/K, respectively. What is the value of AGO at 298 K? AGº=
For the following reaction, N2 (g) + 1/2O2 (g) N2O (g) At 298 K, ΔSsurr = - 275.34 J/K and ΔSsys = -74.3 J/K. Which of the following statements is true? ΔSuniv = -201.04 J/K and the process is nonspontaneous at 298K ΔSuniv = -201.04 J/K and the process is spontaneous at 298K ΔSuniv = 201.04 J/K and the process is spontaneous at 298K ΔSuniv = -349.6 J/K and the process is nonspontaneous at 298K ΔSuniv = -349.6 J/K and the process...
Based on the thermodynamic data below at 298 K, estimate the temperature, in CELSIUS, above which the following reaction would be non-spontaneous. FeO(s s) +Fe(s) +02(g)> Fe20,(s) ДН/ (kJ/mol) So (J/K-mol) FeO(s) -271.9 60.75 Fe(s) Fe203 (a) 618.1°C 27.15 205.0 89.96 0 -822.16 (b) 756.3°C (c) 1235°O (d) 2439°C (e) spontaneous at all temperatures
Based on the thermodynamic data below at 298 K, estimate the temperature, in CELSIUS, above which the following reaction would be non-spontaneous. FeO(s s) +Fe(s) +02(g)>...
4. For the reaction: 2NO2 (g) 6N20(g) at 298 K, The value of AH° and Asº are -58.03 kJ and -176.6J/K, respectively. (a) What is the value of AG° at 298 K? (b) At what temperature would this process be spontaneous?
(6) (1 point) Using the data below, NO(g) + NO2(g) + N203(9) NO(g) + NO2(g) + O2(g) → N205(9) 2 NO2(g) + N20 (9) 2 NO(g) + O2(g) → 2 NO2(g) N205(9) + N2O5(s) AH° = -39.8 kJ AH° = -112.5 kJ AH° = -57.2 kJ AH° = -114.2 kJ AH° = -54.1 kJ compute the heat of reaction for, N2039) + N2O5(s) + 2 N204(9). (6) (1 point) Using the data below, NO(g) + NO2(g) + N203(9) NO(g) +...