Solution:
We are given
P(AUB) = 0.7
P(AUB)c = 1 - P(AUB) = 1 - 0.7 = 0.3
P(AUB)c = 0.3
P(Ac U B) = 0.9
P(B) = P(Ac U B) - P(AUB)c
P(B) = 0.9 - 0.3
P(B) = 0.6
Answer: P(B) = 0.6
Exercise 1 (SOA type). Let us say that we have 2 events A and B which...
1. (10 pts) Consider two events, A and B, for which we have the following probabilities. P(A)=0.5 P(B) = 0.2 P(AB) 0.7 A. Find the probability P( AB) B. Find the probability P(AUB)
statistics, help me please
q19
19/ 20 Let A, B be independent events. If P(A) = 0.4 and P(B) = 0.7, then P(AUB) equals A)0.12 B)0.18 C)0.88 D)O.82 E) 0.72
19/ 20 Let A, B be independent events. If P(A) = 0.4 and P(B) = 0.7, then P(AUB) equals A)0.12 B)0.18 C)0.88 D)O.82 E) 0.72
2. a) Let A and B be two events such that P(A) 4, P(B) .5 and P(AnB) 3 Find P(AUB). b) Let A and B be two events such that P(A)-5, P(B) 3 and P(AUB) .6. Find P(An B)
False Question 3 (1 point) <Venn 5> There are 2 events: A, B with P(A)-0.5, P(B)-0.4, P(AUB)-0.7 Find P(A n B) Question 4 (1 point) Saved <Venn 2 There are 2 events: A, B with P(A)-Q5, P(B)-0.4, PAUB)-0.7
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Let and B be events in a sample space S, and let C = S - (AUB). Suppose P(A) = 0.8, P(B) = 0.2, and P(An B) = 0.1. Find each of the following. (a) P(AUB) (b) P(C) (c) PAS (d) PLAC BC) (e) PLACUBS (1) P(BCnc)