Question

(25pts) 3. For a four resistors n-channel JFET, find the operating points (VGs. Ip, and VDs). Assume Ipss = 5mA, Vp = -4.5V and Ig - 0 Given: Vpp = 12 V, R1 = 2M2, R2 = 1.5M, Rp=6 k 2, Rss = 4 k.,

Answer 1

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from the given information, 14x1.5m op=148 von Then, th= Ro=bka 1M+1.5M Rth = 1M//1.5M = = 8.40. Rialni Vos Then, IMX1.5M 2.5M = 0.6Mr. Mat.se Vem vas } Rss=4k. Then, from the circuit, Then, the simplified circuit is, Into Ro=6k. Nue=VG-Us= 84 - Vs = 8.4.4K Ip. 다. Vps I Rth=0.64.1 von=8.41 vas {Rs=466 as we know Then, that, Ip= Foss (1 - who (1-3.4.cats)? In - sm e)". Then, by seshing As we know that, Io= Foss (1 - was so sm sm (4.5+ Vas)? Thens 20.25 sm 20.25 Vas = 1.34, s. 67 8.4-Uus (4.5+ 4s) 8.4 Vas = 0.98 (vast 4.5). Then 4K 8.57-1.02 Vas 20.25 + quas thus then, vag+ 10.00 vas +11.6820 By solving. we get, Who a = -1.340 ㅌ C: Vast (-124) Io = Foss (1- vas up Ip = 2.40mA (( ما (2) quen, sm ( - Cher) by solving weget Then, Nos = Votre : -1.34 - (-4.5). Then, Nos = 3.161