Question

Please solve Discussion part as well , will upvote

Question 4 (1 point) Your facility already includes multiple TACO TA 0824 pumps, so using the same pump for a new application has many advantages in terms of spares and maintenance costs. The new application has a design flow of 0.05 m3/s and a head of 65 m pumping water at 20C. The application includes 42 m of useful elevation gain with the rest being losses, so the system curve can be expressed as H = 42 + 23*(Q / 50)** 2 for H in metres and Q in litres/s The TA 0824 running at 3500 RPM appears to be in the right range. (Look towards the end of the curve book.) We ordered one with a 9.00 inch impeller, possibly over design capacity. What flow rate would you get from the 9.00 inch impeller installation with all valves fully open? (pick the closest) Discussion: Provide a copy of the manufacturer's pump curve, showing the operating points you considered to reach your conclusion.

Answer 1

Solution:

Using system curve equation, garph is plotted on the pump curve ( TACO TA 0824 at 3500rpm).

H = 42+ (23* (Q/50))

where, H is in

and Q is in

For , following data has been calculated using Excel sheet.

Q(gpm) Q (4/5) 0 250 500 H(m) H(ft) ol 42] 137.7953 15.7725 44.2887| 145.3041 31.545 51.1548| 167.8307 47.3175 62.5983 205.375 63.09 78.6192 257.937 78.8625 99.2175 325.5168 750 1000 1250

Pump 250 ft H(H) operating point system curve googpm Q (gpm)

From the intersection of pump curve and system curve for 9 inch impeller , the operating point is found to be,

$Q=990gpm=990*0.06309=62.45L/s$

${1gpm=0.06309L/s}$

$Q=62L/s$

Therefore, correct option is $Q=62L/s$ .

Manufacturer's pump curve can not be submitted as it comes under the Copy right or Plagiarism issue.