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(11%) Problem 8: A circular wire loop of radius r = 0.35 m and resistance R= 11 12 rotates about a shaft through its diameter

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Answer #1

(a)

Integral (B.dA)

B.dA cos (wt)

B.cos wt integral (dA)

B cos 2\pift . \pi r^{2}

so,

\phi = B \pi r^{2} cos ((2\pift)

_____________________

(b)

at t = 0.121 s

\phi = 0.21 * \pi * 0.35^2 cos ( 2\pi * 5.5 * 0.121)

\phi = 0.081 Wb

_____________________

(c)

emf = d\phi / dt

emf = 2\pi ^{2}r ^{2} f B sin (2\pift)

___________________________

(d)

at t = 0.121 s

emf = 0.2 V

________________

(e)

I = emf / R

I = 2\pi ^{2}r ^{2} f B sin (2\pift) / R

______________

(f)

I = 0.018 Amps

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