Question

! Required information A 1.75-in. steel plate and a 1-in. gray cast iron plate are compressed with one bolt and nut. The bolt is 12 in-13 UNC. A 12 N American Standard plain washer is used under the head of the bolt and under the nut. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Determine the material stiffness. The material stiffness is Mlb/in.

Answer 1

bata from the given question Bolt is Ź in -13 UNC ² N. Gray cost steel plale - 1.75in Iron plate-lºn from table: The Washer thickness 93 0.095 in thus (-2+1+2 x 0.095 = 3 + 0.19 4- 3.1980 The nut height = 7 iG LIH L = 3.19+ 7 in 구 = 3:19+0.43 = 3.6275 L~ 3.75 in LT = 20th 210:5)+0.25 to.25 = LT = 1.25ºn ld = L-LT 3:75-1.25 Id=2.5in At : l-ld = 3.19-205 tt = 0.69in

I(0.5? Ad 2 4 0.78 5x0.25 from Ad=0.1963 in 2 table AL=o.illa in2 kelb= ADALE Adolttazla kb Ô• 10 3 X 2 - 4 19 30 0.1963 X0.69 +0.1419x (2-5) 0.8356 0.1354 +0.3547 0.8356 o ugo1 kb = 1.705 mibelin 0.095 1 steel 1.25" Grey cast Iron 0.5" الي (9.0 0486" 0.75! tach steel washer frustum E: 0.0950 da. 0.531 in Da 0.75 in E = 30 mpsi

ki = 3 0.5774 TT (30) (0.531) an 1-155(0-095) + 0.75-0-531)(0-750531)] 1-155(0.095) + 0.75 +0.531) (0.75-6-530)] 28.996 lo plo.109 +0.219) (1.281) f[0.109 7.1.281) (0.219] 28.896 1 int 0.328 X 1-281 1.39 X 0.219 28-896 in [ 0:46.2014 0.30 414 28.896 In(1-38) 29.896 0.322 K = 89.73 mlbplin The plote, top steel frustum t-1.2510 d=o.sin D=0.75+ 210.095) tan 300 D-0:86010 E = 30mpsi = K2 my 0:5774.1 (30)0:5 1.15$(1-25) + 0.860-0.5) (0.86005) 1-155(1:25)+0.560 10.5] (0.860-0.5) 27.2009 (1-443 +0.36) (1-36) 1.443+1-36) (0-36] end

27,209 a 17 in L 1.802 X 1.36 X0:30 2.803 x 0.36 27.209 2.45 1.009 27.204 0:887 (K2= 30.675 mebf in Top Plote, lowe steel frustom t-ogin do sin D=0.860 +261) Tan30% 0 = 2.015 in E =30 mpsi 0.5774TT (30) 00:5) f (1.155)(0-5)+2:015-0.5) (2.01510:53) C1.155(0.5)+2.0!5+0.5)(2-015-05) K3= ( 213560312-05 405) 27. 209 (600513 (0.977 + 1.515) C2.515)) 0.577† 2.515)(1.515) 27. 209 en L 2.092 X 2.515 3.092 X 10515 27.2011 5.261 in 4.634) 27.209 0.116 K3 = 234.56 'm abflin

5 cast iron t=lin d=o.sin D=0.75+ 210-095) Tan 300 D = 0.860in E-1405 mpsi: 0.5774 TI (14.5) (0.5) ku= (1.155(0.5) +0.860-05] [0-8660.5) en (1.155(0-5)+0.860+0.5) (6-860-05), 13:151 11 in China 5.937 X1-36 1.937*0.36 t t k3 ky = 15.99 mibf ling km = ( 2 4 + F2 tu) (Sans+ 30.67 * 23.4.56 (0.022 +0.032 +0.004 +0.062) (0.12) = t. 15.99 = 8.3 km-8:3 mlbflin