Question

1) A survey of 1,092 adults was​ asked, "Do you feel overloaded with too much​ information?" Suppose that the results indicated that of 543 ​males, 230 answered yes. Of

549 females, 271 answered yes. Construct a contingency table to evaluate the probabilities..

a. What is the probability that a respondent chosen at random indicates that​ he/she feels overloaded with too much​ information?

nothing

​(Round to three decimal places as​ needed.)

b. What is the probability that a respondent chosen at random is a female and indicates that​ he/she feels overloaded with too much​ information?

nothing

​(Round to three decimal places as​ needed.)

c. What is the probability that a respondent chosen at random is a female or who feels overloaded with too much​ information?

nothing

​(Round to three decimal places as​ needed.)

d. What is the probability that a respondent chosen at random is a male or a​ female?

nothing

​(Round to three decimal places as​ needed.)

3. In​ 2008, the per capita consumption of soft drinks in Country A was reported to be 18.12 gallons. Assume that the per capita consumption of soft drinks in Country A is approximately normally​ distributed, with a mean of 18.12 gallons and a standard deviation of 4 gallons. .

a. What is the probability that someone in Country A consumed more than 14 gallons of soft drinks in​ 2008?The probability is

​(Round to four decimal places as​ needed.)

b. What is the probability that someone in Country A consumed between 5 and 8 gallons of soft drinks in​ 2008?The probability is

​(Round to four decimal places as​ needed.)

c. What is the probability that someone in Country A consumed less than 8

gallons of soft drinks in​ 2008?The probability is

​(Round to four decimal places as​ needed.)

d.97​% of the people in Country A consumed less than how many gallons of soft​ drinks?The probability is 97​% that someone in Country A consumed less than

gallons of soft drinks.

​(Round to two decimal places as​ needed.)

Answer 1

Given :

A survey of 1,092 adults was​ asked, "Do you feel overloaded with too much​ information?" Suppose that the results indicated that of 543 ​males, 230 answered yes. Of 549 females, 271 answered yes.

The contegency table from the given information :

	Free overloaded	not free overloaded	Total
Male	230	313	543
Female	271	278	549
Total	501	591	1092

a) The probability that a respondent chosen at random indicates that​ he/she feels overloaded with too much​ information :

P(feels overloaded) = n(feels overloaded)/n(Total trial)

= 501/1092

= 0.459

b) The probability that a respondent chosen at random is a female and indicates that​ he/she feels overloaded with too much​ information :

P(Female and feels overloaded) = n(female who feels overloaded)/n(Total trial)

= 271/1092

= 0.248

c) The probability that a respondent chosen at random is a female or who feels overloaded with too much​ information :

P(female or feels overloaded) = P(female) + P(feels overloaded) - P(female and feels overloaded)

= 549/1092 + 501/1092 - 271/1092

= (549+501-271)/1092

= 779/1092

= 0.713

d) The probability that a respondent chosen at random is a male or a​ female :

P( male or female ) = P(male) + P(female) - P(male and female)

= 543/1092 + 549/1092 - 0

= (543+549)/1092

= 1092/1092

= 1.000

According to the HOMEWORKLIB POLICY answered only first question for remaining please repost the question.