Question

Compute the Pearson Correlation Coefficient, r, for the following data

X	Y
1	7
3	4
5	3
4	2
2	4

Note: If it is a decimal number with two or more than two places, leave only two decimal places after the decimal point and do not round.

If it is a negative correlation, please do not forget to include the negative sign.

1a)

The Pearson Correlation, r is:

1b)

The correlation is

Group of answer choices

a) Medium and negative

b) Large and negative

c)Large and positive

d)Medium and positive

1c)

The alternative hypothesis in symbols for a two-tailed test is

Group of answer choices

a) H1: r = 0

b) H1: ρ ≠ 0

c) H1: ρ = 0

d) H1: r ≠ 0

1d)

If we use a two-tailed test with α = .01, the critical r values are:

Group of answer choices

a) ±0.754

b) ±0.959

c) ±0.805

d) ±0.878

1e)

Your decision is

Group of answer choices

a) Reject the null hypothesis and conclude that there is a significant correlation between X and Y

b) Fail to reject the null hypothesis and conclude that there is a significant correlation between X and Y

c) Reject the null hypothesis and conclude that the correlation between X and Y is not significant

d) Fail to reject the null hypothesis and conclude that the correlation between X and Y is not significant

1f)

Report the results of the correlation in APA

Answer 1

2 Х XY x2 - 그 3 4 9 7 12 15 5 3 49 16 9 4 16 8 2 25 16 4 4 2. EX = 15 EY = 20 n = 5 EX? = 55, EY2=94, EXY=50 (19) Pearson Pearson correlation coefficient is. nEXY) - (Ex) (EV) En (582) - (EX)2 ] [ n (582) -(8712] 5(50)-(15) (20) 15 (55)- (15)?] [ 5 (94)-(2012) = -0.84 (16) The correlation is - 131 (b) large and negative (10) The alternative hypothesis in symbols for a two- tailed test is. (6) Hiigo (id) If we use a two-tailed test with d=0.01 the nitical & values are i (6) ► 0.959 - [ Using Pearson Correlation table for x=0.01 and df = -2=3].

(le) Decision is - (b) fail to reject that there is reject the the null by pothesis and conclude a significant correlation between X and Y.