Question

T. Cable 1 Example of Static Equilibrium Balancing a leaning beam: F-T=0] =F=T, F = 5047 N F, - Mg - mg = 0) = F, - 515g = 0 F. Beam com Rope mg X Hing al. – bMg - 2 mg = 0) (3) M Beam = 1.9T. – 2.5.430g – 24.85g = 0) (3) Say, M = 430 kg, m = 85 kg, a = 1.9 m, b = 2.5 m From (3): 1.9T. = 10535+1041.25 .:.T. = 6100 N F = E +F;? .::F, = 6100 N 16100² +50472 = 7917 N Be sure to attend the recitations this week for practice!

Answer 1

= 1.9m Aus - a ri Ten てた z = 6100x1.9 2= 11590 Nm direction : counter clockwise 11590 Nm (counter clockwise) so