Question

m H C A shown in the picture, a 373 g mass slides down a curved incline then collides with a spring. The spring constant of the spring is 136 N/m. Assume that friction is negligble in these problems. (A) If the mass starts from rest at a height of 1.43 cm, what is the final compression of the spring when the mass comes to rest? Assume the spring is initially uncompressed. 0.02772560401 m (B) If the mass initially compresses the spring 1.26 cm, what is the maximum height the mass rises to on the incline? Assume the mass released from rest. 0.00295335 m C) If the mass is released from rest at a height of 1.43 cm, what is the compression of the spring when the mass has a speed of 42.4 cm/s? 0.01490134292m

Answer 1

(A) potential energy, righ = kx² - 373 £x136x2? x 9.8 x 1:43 loo Х = 373 100 m=373 g loro ng h=1043cm = 1.43 100 ka136 N/m m --> x = 0.0277256041 m. - final compression = 0.0277256041 m.

(6) x=1-26 cm migh = 1+ kan 2 1-26 100 m. 2 1:26 X136 X 373 x9.88h = 100 1000 =) h = 0.00295335 m. .: Mass released foom height -0.00295335 m. (e) when mass move with speed = 42 cm/s v= 42 mis: 100 kinetic energy = 1/2 mer 1 mur 1) .. Ikar 2 x 1 mor 373 1000 42 100 X 136 * x К. .4 m. 4.83 80 29 X 10 = 0.0004838029 m. =0.000 48 38029 mi .. Compression