Question

Consider the 10.0 kg motorcycle wheel shown in the figure. A Assume it to be approximately an annular ring with an inner radius of R1 = 0.280 m and an outer radius of R2 = 0.300 m. The motorcycle is on its center stand, so that the wheel can spin freely. (a) the drive chain exerts of 2060 Nat radius of 5.0 cm, hat is the angular acceleration (in rad/s2) of wheel? rad/s2 (b) What is the tangential acceleration in m/s2) of a point on the outer edge of the tire? m/s2 (c) How long (in s), starting from rest, does it take to reach an angular velocity of 80.0 rad/s?

Answer 1

According to HOMEWORKLIB POLICY we have to solve the first question

Solution (as we have the Equations a=Id I = 0.5 MCR, 2+R2²) 30.5X10 (0.280 ?+ 0.1002) 2 kgme I- 0.842 T= rf E 0:05 X 2060 103 Nm da? 1 00842 = 103 1 22.32 hadise 3 (5) Tangential deceleration ат. К, А 50.300 X 122:32 = 36:696 mis? (C) Here 80=de 80=122.324 t = 0.65 see