Question

14-5 points A 3. Q resistor is connected in parallel with a 6. Q resistor. This pair is then connected in series with a 4. 2 resistor. These resistors are connected to a battery. What will happen if the 3. resistor burns out, i.e., becomes an infinite resistance? Show your work. A) The power dissipated in the circuit will increase. B) The power dissipated in the circuit will increase. C) The current in the 4.12 resistor will drop to zero. D) The current in the 6.2 resistor will increase.

Answer 1

14. mm w 3x6 6+3 Ho Equivalent resistance, Reqa + 4 = bar - unent, I. Ť Ampere the 32 burns out, it becomes infinite resistance, definitely open cirunt. Therefore, the crunt can be redrawn as, Nnus) if it will act 6.02 42 M V → Equivalent resistance, Reqa 6+4 2 10-2. - Cullent 12 V 2 Ampere 2 <I, Therefore, the power dinipated in the event will decrease. (p=12R) بيا