A small block of mass m1 is released from rest at the top of a curve-shaped,...

Question

Question

A small block of mass m1 is released from rest at the top of a curve-shaped, frictionless

wedge which sits on a frictionless horizontal surface as shown. The height of the wedge

is h = 5 m. When the block leaves the wedge its velocity relative to the ground is

measured to be 4.00 m/s to the right as shown in the figure. If the mass of the block is

doubled to become 2m1, what will be its speed when it leaves the wedge?

science physics

Answer 1

Answer #1

By energy conservation:

(Potential energy at top )=(kinetic energy. while leaving the wedge)

Mgh=Mv²/2

v=√(2gh)

Fron the derived formula,we came to know that the speed while leavibg the wedge does not depend on tha mass of block.

So the spees of block of mass 2m1

v=4.00m/s

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Answer 2

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