Homework Answers
To determine expected counts
Given : n = 100 and pmf given for values i : 1,2,3 and 4 is given.
Here to calculate expect counts we used following formula
Expected count = n * P(X=X)
| i | 1 | 2 | 3 | 4 |
| Pi | 0.13 | 0.32 | 0.21 | 0.34 |
|
Expected counts |
400*0.13 = 52.00 | 400*0.32 = 128.00 | 400*0.21 = 84.00 |
400*0.34 = 136.00 |
The expected count for outcome 1 is 52.00
The expected count for outcome 2 is 128.00
The expected count for outcome 3 is 84.00
The expected count for outcome 4 is 136.00
Add Answer to:
please help!
Determine the expected count for each outcome n=400 1 2 3 4 P, 0.13...
Determine the expected count for each outcome. N=633 i 1 2 3 4 pi 0.16 0.35...
Determine the expected count for each outcome. N=633 i 1 2 3 4 pi 0.16 0.35 0.16 0.33 The expected count for the outcome 1 ___________.(Round to two decimal places as needed). The expected count for outcome 2 is____________.(Round to two decimal places as needed). The expected count for outcome 3 is___________.(Round to two decimal places as needed) The expected count for outcome 4 is___________(Round to two decimal places as needed)
Y Determine the expected count for each outcome. n= 818 2 3 4 Pi 0.12 0.43...
Y Determine the expected count for each outcome. n= 818 2 3 4 Pi 0.12 0.43 0.19 0.26 The expected count for outcome 1 is (Round to two decimal places as needed.) The expected count for outcome 2 is (Round to two decimal places as needed.) The expected count for outcome 3 is (Round to two decimal places as needed.) The expected count for outcome 4 is (Round to two decimal places as needed.)
Determine the expected count for each outcome. nequals=906906 i 1 2 3 4 pi 0.160.16 0.320.32...
Determine the expected count for each outcome. nequals=906906 i 1 2 3 4 pi 0.160.16 0.320.32 0.190.19 0.330.33 The expected count for outcome 1 is nothing . (Round to two decimal places as needed.) The expected count for outcome 2 is nothing (Round to two decimal places as needed.) The expected count for outcome 3 is nothing (Round to two decimal places as needed.) The expected count for outcome 4 is nothing (Round to two decimal places as needed.)
Question 3 (1 point) Given the following probability distribution, what is the expected value? Outcome P(Outcome)...
Question 3 (1 point) Given the following probability distribution, what is the expected value? Outcome P(Outcome) 31 0.12 25 0.08 2 0.06 14 0.21 40 0.00 6 0.53 Round to 2 decimal places as needed.
Chapter 7, Section 2, Exercise 032 X Incorrect. Find the expected count and the contribution to...
Chapter 7, Section 2, Exercise 032 X Incorrect. Find the expected count and the contribution to the chi-square statistic for the (A, F) cell in the two-way table below. G Total 149 56 287 30 113 Total 130 161 131 127 549 Round your answer for the expected count to one decimal place, and your answer for the contribution to the chi-square statistic to three decimal places, x Expected count = contribution to the chi-square statistic = 1 Click if...
ment PRIN Chapter 7, Section 2, Exercise 032 Find the expected count and the contribution to...
ment PRIN Chapter 7, Section 2, Exercise 032 Find the expected count and the contribution to the chi-square statistic for the (Treatment, Agree) cell in the two-way table below. Agree Neutral Disagree Disagree Control 36 49 Treatment 63 4111 4 1 3 18 8 Round your answer for the excepted count to one decimal place, and your answer for the contribution to the chi-square statistic to three decimal places. Expected count contribution to the chi-square statistic Click if you would...
P(X=0)=0.13 P(X=1)=0.17 P(X=2)=0.30 P(X=3)=0.32 P(X=4)=0.08 P(X=4)=0.08 is wrong and , i need help Isabel Briggs Myers...
P(X=0)=0.13 P(X=1)=0.17 P(X=2)=0.30 P(X=3)=0.32 P(X=4)=0.08 P(X=4)=0.08 is wrong and , i need help Isabel Briggs Myers was a pioneer in the study of personality types. The personality types are broadly defined according to four main preferences. Do married couples choose similar or different personality types in their mates? The following data give an indication. Similarities and Differences in a Random Sample of 375 Married Couples Number of Similar Preferences Number of Married Couples All four 32 Three 120 Two 112...
use n=6 and p=0.15 to complete parts a through d please Use n 6 and p...
use n=6 and p=0.15 to complete parts a through d please
Use n 6 and p 0.15 to complete parts (a) through (d) below. (a) Construct a binomial probability distribution with the given parameters x P(x) 0 0.3771 1 0.3993 2 0.1762 3 0.0415 4 0.0055 5 0.0004 6 0.0000 (Round to four decimal places as needed.) (b) Compute the mean and standard deviation of the random variable using #x-O (Round to two decimal places as needed.) x- [x-P(x) and...
This Quiz: 6 pts possit Question Help A researcher wanted to determine whether certain accidents were...
This Quiz: 6 pts possit Question Help A researcher wanted to determine whether certain accidents were uniformly distributed over the days of the week. The data show the day of the week for n 300 randomly selected accidents. Is there reason to believe that the accident occurs with equal frequency with respect to the day of the week at the a=0.05 level of significance? B Click the icon to view the table. Let the proportion of accidents on day I,...
Determine the probability P(3) for a binomial experiment with n - 12 trials and the success...
Determine the probability P(3) for a binomial experiment with n - 12 trials and the success probability p=0.2. Then find the mean, variance, and standard deviation. Part 1 of 3 Determine the probability P(3). Round the answer to at least four decimal places. P(3)- Part 2 of 3 Find the mean. If necessary, round the answer to two decimal places. The mean is Part 3 of 3 Find the variance and standard deviation. If necessary, round the variance to two...
Y Determine the expected count for each outcome. n= 818 2 3 4 Pi 0.12 0.43 0.19 0.26 The expected count for outcome 1 is (Round to two decimal places as needed.) The expected count for outcome 2 is (Round to two decimal places as needed.) The expected count for outcome 3 is (Round to two decimal places as needed.) The expected count for outcome 4 is (Round to two decimal places as needed.)
Chapter 7, Section 2, Exercise 032 X Incorrect. Find the expected count and the contribution to the chi-square statistic for the (A, F) cell in the two-way table below. G Total 149 56 287 30 113 Total 130 161 131 127 549 Round your answer for the expected count to one decimal place, and your answer for the contribution to the chi-square statistic to three decimal places, x Expected count = contribution to the chi-square statistic = 1 Click if...
ment PRIN Chapter 7, Section 2, Exercise 032 Find the expected count and the contribution to the chi-square statistic for the (Treatment, Agree) cell in the two-way table below. Agree Neutral Disagree Disagree Control 36 49 Treatment 63 4111 4 1 3 18 8 Round your answer for the excepted count to one decimal place, and your answer for the contribution to the chi-square statistic to three decimal places. Expected count contribution to the chi-square statistic Click if you would...
use n=6 and p=0.15 to complete parts a through d please
Use n 6 and p 0.15 to complete parts (a) through (d) below. (a) Construct a binomial probability distribution with the given parameters x P(x) 0 0.3771 1 0.3993 2 0.1762 3 0.0415 4 0.0055 5 0.0004 6 0.0000 (Round to four decimal places as needed.) (b) Compute the mean and standard deviation of the random variable using #x-O (Round to two decimal places as needed.) x- [x-P(x) and...
This Quiz: 6 pts possit Question Help A researcher wanted to determine whether certain accidents were uniformly distributed over the days of the week. The data show the day of the week for n 300 randomly selected accidents. Is there reason to believe that the accident occurs with equal frequency with respect to the day of the week at the a=0.05 level of significance? B Click the icon to view the table. Let the proportion of accidents on day I,...
Determine the probability P(3) for a binomial experiment with n - 12 trials and the success probability p=0.2. Then find the mean, variance, and standard deviation. Part 1 of 3 Determine the probability P(3). Round the answer to at least four decimal places. P(3)- Part 2 of 3 Find the mean. If necessary, round the answer to two decimal places. The mean is Part 3 of 3 Find the variance and standard deviation. If necessary, round the variance to two...
Most questions answered within 3 hours.
-
Where is the error in this code sequence?
String s1 = "Hello";
String s2 = "ello";...
asked 10 months ago -
Financial data for Joel de Paris, Inc., for last year
follow:
Joel de Paris, Inc.
Balance...
asked 10 months ago -
Consider this reaction:
Al2(SO4)3 (aq)+ BaCl3
(aq) Al2Cl6 (aq)- +
3BaSO4(s) . What is the...
asked 10 months ago -
Suppose that Savneet is considering increasing her
recent random sample from 20 car rentals to 40...
asked 10 months ago -
Trucks arrive at an unloading terminal at an average rate of 120
per hour.
Trucks arrive...
asked 10 months ago -
Why are methanol and ethanol completely soluble in water while
octanol is not very little soluble....
asked 10 months ago -
A facilities manager at a university reads in a research report
that the mean amount of...
asked 10 months ago -
When the CuSO4 is rehydrated by adding water to the anhydrous
compound, is this an endothermic...
asked 10 months ago -
A ray of sunlight is passing from diamond into crown glass; the
angle of incidence is...
asked 10 months ago -
A block of mass 0.249 kg is placed on top of a light, vertical
spring of...
asked 10 months ago -
how do the kidneys compensate in the presences of acidosis
a) trigger hyperventilate
b) reserve acid...
asked 10 months ago -
Question 501 pts
The rental rate of capital to the firm increases. Which of the
following...
asked 10 months ago