Question

Question 1 What is the resultant sum of the voltages V1= 100V Z 0° and V2 = 100 V Z 300 ? a. 186.6 V 2150 b. 2001 30° C. 193.2V 2 15° d. 240V Z 30°V

Answer 1

Answer -1

   Given,

   $\small V_{1}=100V\angle 0^{\circ}$

$\small V_{1}=100(Cos0^{\circ}+jSin0^{\circ})=100V$

And

     $\small V_{2}=100V\angle 30^{\circ}$

     $\small V_{2}=100(Cos30^{\circ}+jSin30^{\circ})=100(0.866+j0.5)=(86.6+j50)V$

Now,

The sum ov V₁ and V₂ is,

$\small V=V_{1}+V_{2}$

$\small V=100+86.6+j50$

$\small V=186.6+j50$

$\small V=\sqrt{186.6^{2}+(50)^{2}}\angle tan^{-1}\left ( \frac{50}{186.6} \right )$

$\small V=193.2V\angle15^{\circ}$

Hence, option (c) is correct.