Question

Score: 0 of 1 pt 2 of 3 (0 complete 5.1.24 Use the figures to calculate the left and right Riemann sums for on the given interval and the given value of n. X2 4- 4- 0 1 2 3 4 0 1 2 3 5 The left Riemann sum for fis (Round to two decimal places as needed.)

Answer 1

OF62 B B f(H 2 +2 C А B C р Е 3 4 5 2 area of the rectangle AB A" A' = AB x ÃA = (2-1)x f (1) = 1x (2+2) = 4 area of the rectangle BCP" B' = BC & BB! = (3-2) + f(2) =1x ( 2 2 2 + 2) = 3 area of the rectangle coole' = CD x cc = (4-3) x f(3) = 1x ( 2 / 2 + 2) = 2 2 + 2 area of the rectangle DEO'D' = DE x DD! =(5-4) X f (4) =1+(2 + 2) = 2.5 Therefore, the right Riemann sum for f is = area of ABA'A' + area of BCR'B' taree of cochel tance of DED'b' = 4+2 + 2/3 + 2 +2.5 = 11.5+ 0.666 = 12.166 ~12.17

+ f(+2= 2 2 +2 B В! Id ID D E В. - 0 2 45 The left Riemann sum for f is area D A BA'A' + areamp cps' tarea ecoce' tarea ded"D' = (2-1)x f (2) + (3-2)x f(3) +(4-3) *f(4) +(5-4) * $(5) [ area of rectangular = length x width] ÁB – 2-1, BA' = f(2), BC – 3-2, CB" = $(3), D = 4-3, Dell = f(A), f(4), DE = 5-4, E = f(5) - 01x (2/2 + 2) + 1+ (1/2 + 2) + 1x ( 2 / 2 + 2) +1+(2 +2) = 1 + 2 + 2 + 2 + 2 + 2 + 2 + 2 270+ 20+15+12 1 t 2 5 30 = 9+ 2 / 2 3 2 | 10:57 317 30 = 10.566 -
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