Question

157q - Chen PART TWO: DATA AND RESULTS Metal: Aluminum Ca=0.217 Cal/ 12)-speeifie quarta Data Item Trial 1 Trial 2 1. Mass of metal 86-bg 50.09 2. Mass of calorimeter 4,4 g 3. Mass of calorimeter and water 124.4 g 4. Mass of water 152-6 g 120g 5. Initial temperature of water 24°C 23°C 6. Initial temperature of the metal 25°C 75°C 7. Final temperature of the mixture 24.11°C 55.7ook See the attachment 8. Calculation of the heat energy gained by the water, O for calculation Trial One: Trial Two: a Garned me G (Tf - Tic) Need to calculate following 152-6-1-(241) - 24) Trial Quid = 16.786 cal 9. What is the heat energy lost by the metal, Q ? Remember, Q = Q Trial One: Trial Two: Q lost = MA. CA. CTF - Tie) Need to calculate following = 86.6.0.217 (241-25) Trial 50*1*(5576) = 18-7922 (-0.89) -1788 cal Quy 10. If Q - me Trial One: Trial Two: 16-73 cal Need to calculate following 86.6g (-0.892) Trial I = 0.217 call goc 11. The accepted value of the specific heat, c, for each metal sample: Trial One: Trial Two: so CAL = 0.217 callge CAI= 0.217 Call I callge

Answer 1

8. Heat gained by water Trouo or guin-mw cw (IQ-T;) Trio Orgain - mai cw (If-T;) = 120X 1X (20.11-zu) a =152.6* 1x(24.11-24) Ta = 16.786 Cou = 13.2 cal a lost 9. Heat lost by metal =m.c. (7f-T;) | Triwe a cost ma CA (Tf -T;) lost = 50X0.217 120.11-25) = 86.6X0.217 (au.1-25) TOGE- 16.73 = -9.66 W 10. Sp. of merce Comer = (AQ) dost MCAT) Trao Thew Cmet 86.6x(20.1)-25) 5ox(24.11-25) Time=0.217 callge met = 0.217ca9c Comér =-16.73 -9.66 11. Accepted verlue of specific heat CA=0.217 Colegic CAL=0.2176/g'c 12 % error Triu Yerror melewired-acceplee! sired receplez accepted = 0.217--0217 xiny. ex100% mease X100 % errore acceptée = 0.217_ 0.212 X100) 0.217 0,217 50%. -07

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