Question

Question 6 2 pts Computation Two objects experience a head-on collision. One object, of mass m2 = 1.85 kg, is moving east at 18.9 m/s, while the other (of mass m2 = 3.93 kg) is moving west at 10.4 m/s. After the collision, the mi object now has a velocity 4.69 m/s to the west. Determine how much kinetic energy was lost during the collision. Note the negative has already been included below. kinetic energy lost = AKE =- Please record your numerical answer below assuming three significant figures.

Answer 1

Given mi = 1,85 kg ū, 18.9 m/sec m2 = 3.93 kg 10.4 m/sec Tot 4,69 m/sec vm m u 2 After collision before collision Using Conservation of linear momentum mu, mg Uz -m, vt mg o 1.85 x 18.9 - 3.93X10.4 = -1.85 x 4,69 + 3.93 V 34.965 40.872 =-8.6765 + 3.93 Oz -5.907 8.6765 +3.93 U 2,7695= 3.93 Uz U₂ = 0.705 m/sec Now Loss in kinetic energy £mz U2 ² - 2 m, 4? - mutta + ДК / / / m ²

Dk= 1 m, (0,²-4, 2) + £ / m₂ (U² - 4,2) ok = { x 1.85 (24.566-357.21) + x3.93 (0:497–108,16) ska -310,072 211.55 DK= -52 1.622 J