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X=04
Q4. 120 marks] For this question, X is the first two digits (from the right) of your student ID. Two machines are under consi
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Answer #1

Let n units are required for breakeven, then

EUAC of first machine = 50000*(A/P,3%,5) + 16000 + 55*n - 6500*(A/F,3%,5)

= 50000*0.218355 + 16000 + 55*n - 6500*0.188355

= 25693.44 + 55*n

EUAC of second machine = 55000*(A/P,3%,7) + 14500 + (04+56)*n - 7000*(A/F,3%,7)

= 55000*0.160506 + 14500 + (04+56)*n - 7000*0.130506

= 22414.29 + 60*n

for breakeven

25693.44 + 55*n = 22414.29 + 60*n

n = (25693.44 - 22414.29) / (60 - 55) = 655.83 ~ 656 (rounding up for breakeven)

Assumption:

Both alternatives will be available infinitely at same cost and same annual costs

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