1. Find the equation of the curve for which is a vex+3 if we know that...
Question 15 The curve with the equation y = 3x + 2x + 5 is shown below. (-1,0) 0 x The curve cuts the x axis at the point A(-1,0) and cuts the y axis at point 8 a) State the coordinates of Point B and hence find the area of the triangle AOB (3 marks) b) Find 3x5 + 2x + 5 dx (3 marks) c) Find the area of the shaded region bounded by the curve and the...
7. Suppose that we have a curve x2 + y2 = 3. Find the equation of the tangent line to the curve at the point (1. -v2).
Find the equation of tangent line to the curve y = x2 – \sqrt[3]{x} at the point (-1,0).
Find an equation for the line that is tangent to the curve y = 3x3 - 3x at the point (-1,0). The equation is y=1 (Type an expression using x as the variable.)
1. Find the equation of the curve passing through the point (1, 1) whose differential equation is (y - yx)dx + (x + xy)dy = 0 (10 marks)
3. Use implicit differentiation for the curve x3 + 3y4 = xy and then find the equation of the tangent line at the point (1,0). 4. Let f(x) = x3 – 2x2. Find the open interval(s) on which the function is increasing or decreasing. Then, find and classify all relative extrema on this interval
(1-2)2 +16 at 3. [8 marks) Find the equation of the tangent to the curve y= = 3.
(1 point) Use implicit differentiation to find an equation of
the tangent line to the curve 2xy3+xy=302xy3+xy=30 at the point
(10,1)(10,1).
(1 point) Use implicit differentiation to find an equation of the tangent line to the curve 2xy3 + xy = 30 at the point (10, 1). The equation -3/70 defines the tangent line to the curve at the point (10, 1).
y^2-3x-4y-1=0
3. Find the equation of the tangent line and the equation of the perpendicular line to the curve y? - 3x - 4y - 1 = 0 at (-2, 1) at the given point. 2 marks.
Find an equation for the tangent line to the curve at the given points. y = x2 – 5x + 4 at the intercepts (1,0),(4,0), and (0,4). y = at (1,0) y= at (4,0) y = at (0,4) Sketch the curve and the tangent line. VA VA X 4 Submit Answer