Question

5. A randomized block design is used in an experiment. There are 4 treatments and 3 blocks. Use the information below to complete the table. b a b a (*; – x)² = 50 {(xy - x)= 712 (#4 - 3)2 = 98 i=1 j=1 i= Degrees of Freedom Sum of Squares Mean Square f P value Source of Variation Treatments Blocks Error Total

Answer 1

#S Given that Treatment (K) = 4 blocks (6) = 3 { (x,x)²98 i1 izija' 2,483-7)+=50 23 (xij - 3)2 712 TSSE (Xij8j+=[712 SST = b â cxi-x)?= 3x 98 =1294 SS8=k () :-3) ²= 4x50=200 SSE = IST - (SST +SSB) = 712- (294+200) = 712-494 s izi MS = SS SSE = 210 df F- MS treat MEDTON (6-1) CK-12 = (3-1)/4-1) - 23 = 6 d.fi treat def Block K-1 = 6-1 2 dof Essor = 3-1 =47 = 3 = 2 ANOVA TABLE ma MS Soc. Difi SS 294 Treadment 3 90 100 2.697 200 2 Blocks 2: 753 218 36.33 6 G8500 Total u 712 where Iss sum of square of total Sott sum of square of Treatment SSB of Blocks SSE -> dif + degree of freedom. of Errors ·