(1 point) When an ac source with a peak potential difference of 32 V is connected...

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(1 point) When an ac source with a peak potential difference of 32 V is connected to a series RLC circuit, the peak current i

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Answer 1

Answer #1

V, 32V then peak current = 1) = 2 2 2 = (3)A 0 = 40 cos- R Z 2 1x-* ! R= 2(c340) = 32(cosyole o R IR=8.17 Xc = 1 ve = 2fc ли

Answer 2

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