We would be looking at the first question all parts here as:
Q1) We are given here that there are 3 males and 1 female.
As we are drawing with replacement here, therefore the
probability of getting a female remains same in both the draws
given as:
p = P(female) = n(Females) / n(Total) = 1/(1 + 3) = 1/ 4 = 0.25
Therefore the number of females in the 2 draws here could be modelled as:
The probability distribution table now is computed here as:
Proportion of Females | Probability |
0 | P(X = 0) = (1 - 0.25)^{2} = 0.5625 |
0.5 | P(X = 1) = 2*0.25*(1 - 0.25) = 0.375 |
1 | P(X = 2) = 0.25^{2} = 0.0625 |
These are the required probabilities here.
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x Refer to the accompanying data set and construct a 90% confidence interval estimate of the mean pulse rate of adult females, then do the same for adult males. Compare the results. Click the icon to view the pulse rates for adult females and adult males. Pulse Rates Construct a 90% confidence interval of the mean pulse rate for adult females. | bpm<<bpm (Round to one decimal place as needed.) Pulse Rates (beats per minute) e Construct a 90% confidence...
Refer to the accompanying data set and construct a 90% confidence interval estimate of the mean pulse rate of adult females; then do the same for adult males. Compare the results. Click the icon to view the pulse rates for adult females and adult males. Pulse Rates Construct a 90% confidence interval of the mean pulse rate for adult females. x bpm<u<bpm (Round to one decimal place as needed.) Pulse Rates (beats per minute) Construct a 90% confidence interval of...
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on ма m Question Help Refer to the accompanying data set and construct a 90% confidence interval estimate of the mean pulse rate of adult females; then do the same for adult males. Compare the results. Click the icon to view the pulse rates for adult females and adult males Construct a 90% confidence interval of the mean pulse rate for adult females. bpmu<bpm (Round to one decimal place as needed.) Construct a 90% confidence interval of the mean pulse...
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