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A transformer connected to a 120V (rms) AC line is to supply 12 kV (rms) for a neon sign. To reduce shock hazard, a fuse is t
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Answer #1

V_{1} = 120 V

V_{2} = 12 kV= 12\times 10^{3} V

I_{2} = 2.0 mA= 2.0\times 10^{-3} A

I_{1} V_{1} =I_{2} V_{2}

I_{1} =\frac{I_{2} V_{2} }{V_{1}}

I_{1} =\frac{2.0\times 10^{-3}A\times 12\times 10^{3} V }{120 V}

I_{1} =0.20 A

the current (rms) in the primary circuit is I_{1} =0.20 A

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