If ΔS for the following reaction is 101 in J/K, what is the value of Sº...

Question

Question

If ΔS for the following reaction is 101 in J/K, what is the value of Sº for A in J/molK?

2A + 7B → 4C + 5D

Sº_B= 54 J/molK

Sº_C= 149 J/molK

Sº_D = 82 J/molK

science chemistry

Answer 1

Similar Homework Help Questions

A spontaneous reaction has a value of ΔH° of -11.8 kJ and ΔS° of -61.4 J/K....

A spontaneous reaction has a value of ΔH° of -11.8 kJ and ΔS° of -61.4 J/K. At what temperature does this reaction become nonspontaneous? 1. 192K 2. 83.7 K 3. 229 K 4. 273 K
For the reaction ΔH°=+61.14 kJ and ΔS° = +132 J/K at 25°C. At what For the...

For the reaction ΔH°=+61.14 kJ and ΔS° = +132 J/K at 25°C. At what For the reaction ΔH°=+61.14 kJ and ΔS° = +132 J/K at 25°C. At what minimum temperature will the reaction be spontaneous?minimum temperature will the reaction be spontaneous? Select one: a. 479 K b. 500 K c. 463 K d. 571 K e. 2904 K
For a reaction, ΔH = – 249 kJ and ΔS = – 278 J/K. What is...

For a reaction, ΔH = – 249 kJ and ΔS = – 278 J/K. What is the maximum temperature at which the reaction is spontaneous?

Calculate the ΔS°rxn of the following reaction at 225°C and standard pressure. (Answer in J/mol x...

Calculate the ΔS°rxn of the following reaction at 225°C and standard pressure. (Answer in J/mol x K) C2H4 (g) + 3O2 (g) ---> 2CO2 (g) + 2H2O (g) ΔHºf, kJ/mol Sº, J/mol•K ΔGºf, kJ/mol C2H4(g) 52.3 219.5 68.1 O2(g) 0 205.0 0 CO2(g) -393.5 213.6 -394.4 H2O(g) -241.8 188.7 -228.6
For a particular reaction at 205.1205.1 °C, ΔG=−45.90 kJ/molΔG=−45.90 kJ/mol, and ΔS=395.61 J/(mol⋅K)ΔS=395.61 J/(mol⋅K). Calculate ΔG...

For a particular reaction at 205.1205.1 °C, ΔG=−45.90 kJ/molΔG=−45.90 kJ/mol, and ΔS=395.61 J/(mol⋅K)ΔS=395.61 J/(mol⋅K). Calculate ΔG for this reaction at −6.1−6.1 °C.
Consider the following reaction at 298 K. C(graphite)+2H2(g)⟶CH4(g)ΔH∘=−74.6 kJ and ΔS∘=−80.8 J/KC(graphite)+2H2(g)⟶CH4(g)ΔH∘=−74.6 kJ and ΔS∘=−80.8 J/K...

Consider the following reaction at 298 K. C(graphite)+2H2(g)⟶CH4(g)ΔH∘=−74.6 kJ and ΔS∘=−80.8 J/KC(graphite)+2H2(g)⟶CH4(g)ΔH∘=−74.6 kJ and ΔS∘=−80.8 J/K Calculate the following quantities. ΔSsys=ΔSsys J/K ΔSsurr= J/K ΔSuniv= J/K

For a particular reaction, ΔH = -32 kJ and ΔS =-98 J/K. Assume that ΔH and ΔS do not vary withtemperature. A) At wha...

For a particular reaction, ΔH = -32 kJ and ΔS =-98 J/K. Assume that ΔH and ΔS do not vary withtemperature. A) At what temperature will the reaction have ΔG= 0? B) If T is increased from that in part A, will the reaction bespontaneous or nonspontaneous?
What is the ΔS° at 298 K for the following reaction? 2 O3(G) ---- 3 O2(G)...

What is the ΔS° at 298 K for the following reaction? 2 O3(G) ---- 3 O2(G) Substance ΔS° (J/mol·K) O2(g) 205.0 O3(g) 238.8
For a given reaction, ΔH = +20.8 kJ and ΔS = +27.6 J/K. The reaction is...

For a given reaction, ΔH = +20.8 kJ and ΔS = +27.6 J/K. The reaction is spontaneous __________ A) At T < 754 K B) At T > 133 K C) At all temperatures D) At T > 754 K E) At T < 133 K

Given the information Sº = 341.0 J/K AS = -120.0 J/K A+B - 2D AH =...

Given the information Sº = 341.0 J/K AS = -120.0 J/K A+B - 2D AH = -757.9 kJ CD AH = 384.0 kJ calculate AGⓇ at 298 K for the reaction A+B +20 AG = TOOLS x10