Question

PENDULUM MEASUREMENTS Four students in the lecture hall timed ten full cycles of the L = 1.22 m long pendulum, oscillating left and right. Here are their time measurements: Student Their stopwatch time 22.21s 22.215 Dominik Kayne Abigail Sabrina 22.20 s 22.32 s Use the above table of data to calculate the average time for one full cycle: 8.894 s. 2.2235 s 88.94 s. 22.2355

Answer 1

The time taken for 10 oscillations by 4 students are

22.21s , 22.21s , 22.32s , 22.20s

The average time required for the 10 oscillations be

$avg = \frac{22.21 + 22.21 + 22.32 + 22.20}{4} = 22.235 s$

The time period is

aug = 22.235 10 = 2.2235 s

hence the ans is 2.2235s