Question

A point charge (g = +6.00 nC, m = 1.00 x 10-15 kg) is fired from the negative plate of a parallel plate capacitor with an initial speed of vo = 3.50 x 105 m/s. When the particle has traveled two-thirds the distance to the positive plate, its speed is vy=2.34 x 105 m/s. If the electric field strength in the capacitor is E = 2.89 x106V/m, what is the capacitor's plate separation, d? a. Use energy conservation to write an expression for d. Your expression should be simplified and contain only the variable names given in the problem. b. Use your expression from (a) to calculated. Submit this answer below. Instructions: Enter your result below and include units but do not use prefixes. Be mindful of significant figures. Note: Use "E" for scientific notation. For example, 0.012 = 1.25-2

Answer 1

(6) do 3x1x16" ((3,5)_(2.34)] 10'0. 4x 2.89x108x6x109 6 -3 = 2.93 x 10 m m = d= 0.293 x 102 - d= 2.93 E-3.