(a)
| Source | SS | df | MS | F | p-value |
| Treatment | 10,971.04 | 2 | 5,485.522 | 3.22 | .0506 |
| Error | 68,181.93 | 40 | 1,704.548 | ||
| Total | 79,152.98 | 42 |
(b) The hypothesis being tested is:
H0: µ1 = µ2 = µ3
Ha: Not all means are equal
The p-value is 0.0506.
Since the p-value (0.0506) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we cannot conclude that the three groups of athletes can be considered to have the same mean weight.
(c) r² = 10,971.04/79,152.98 = 0.139
13.9% of the variation in the model is explained.
Below are weights (in pounds) of three groups of athletes. Athlete Group 1 Athlete Group 2...
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