Question

15124. Determine the net electric flux through the surface shown by the broken line at the right. 4. =-58, +65eq+50e, 4.-36e, and q. --44e. Answer:

Answer 1

$\!\!\!\!\!\!\!\!\!$According to Gauss's law, flux through a closed surface is related to the charge enclosed by the surface as,$\\\\ $Flux through the surface, $\Phi_E=\oint \vec{E}.\vec{dS}=\frac{Q_{enclosed}}{\epsilon_0}\\\\ $Here, charge enclosed by the surface, $\\\\Q_{enclosed}= q_1+q_3+q_4= -58e+50e-36e=-44e\\\\ $Flux through the surface, $\Phi_E =\frac{-44\times 1.6\times 10^{-19}}{8.85\times 10^{-12}}=-7.95\times 10^{-7}$Nm$^2$/C$$