Question

PLEASE HELP ME WITH THIS TASK 3.1 (FLOWCHART) AND TASK 3.2 (SOURCE PROGRAM). THANK YOU!

Hint: the number array in task 2 is work for task 3 in figure 1.  

Given below is a partially completed C program, which you will use as a start to complete the given tasks. #define SIZE 9 #include <stdio.h> int compareAndCount (int[], int[]); double averageDifference (int[], int[]); void main() { } int compareAndCount(int arr1[SIZE], int arr2[SIZE]) { int count = 0; for (int i = 0; i < SIZE; i++) { if (arri[i] > arr2[i]) count++; } return count;

Answer 1

Program logic:

• In the function averageDifference(), set sum = 0
• then loop through each element of arr1
  • subract the current element of arr1 and its counter part in arr2.
  • add the result to sum
• once the fucntion is out of the loop, divide the sum by SIZE and return the value

flow chart

오로 false HITE

function definiton:

double averageDifference(int arr1[SIZE], int arr2[SIZE]){
int sum = 0;
for(int i = 0; i<SIZE; i++){
sum += arr1[i]-arr2[i];
printf("arr1[%d] - arr2[%d]: %d\n", i,i,arr1[i]-arr2[i]);
}
return (double)(sum/SIZE);
}

program to call this function:

#define SIZE 9
#include <stdio.h>

int compareAndCount(int[], int[]);
double averageDifference(int[], int[]);

void main(){
int arr1[] = {111,2,333,44,55,16,27,83,99};
int arr2[] = {-11,22,13,88,99,101,34,25,-22};
double ave = averageDifference(arr1,arr2);
printf("The average difference between items in array A and array B: %.2f\n", ave);
}

double averageDifference(int arr1[SIZE], int arr2[SIZE]){
int sum = 0;
for(int i = 0; i<SIZE; i++){
sum += arr1[i]-arr2[i];
printf("arr1[%d] - arr2[%d]: %d\n", i,i,arr1[i]-arr2[i]);
}
return (double)(sum/SIZE);
}

output:

arr1[0] arr2[0]: 122 arr1[1] - arr2[1]: -20 arr1[2] - arr2[2]: 320 arr1[3] - arr2[3]: -44 arr1[4] - arr2[4]: -44 arr1[5] - arr2[5]: -85 arr1[6] - arr2[6]: -7 arr1[7] arr2[7]: 58 arr1[8] arr2[8]: 121 The average difference between items in array A and array B: 46.00