Question

MA OTKR) Practice-5 variable K-Map.pdf At 1.38 MB) Use Kamaugh maps to design lowest cost circuits for the following function with NOT, AND dort gates. To find the lowest costs add to the both the SOP form of the circuit and POS form of the circuit and compare their cost to find the best cast circut House Karnaugh maps for both SOP and Pos forms and then cotain the simple expression by covering is for SOP form or ces der POS form. Then design circuits and compare the cost Circle your lowest cost solution You should consider two equivalent circuits to compare col which means you need to minimiza mapoor example 500.1.6. )-bytovering and-POS 2. 3. 4. 5) by covering Os as shown in the dess. Upload your work on Blackboard in pdf form. Library copiers can slow your bod document or you can use a scanner app on your smartphones Note There are some worked out examen in attachments above for this HW Study them to practice your des before maringowe Den bok 121 - M2.4.5.6.77 (a) - Imi 2.3.5.6.7.1.10.13.151 14) - M 2.5.131415+00.40.3.10.11 151 - m, 1,4,5,6,8 10, 11, 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 24, 26, 27, 20.30311

please solve number 2 and number 5

Answer 1

2 7 = 1M (2, 4,5,6,77 this function is in Pas form (as Ilm is given the no. of i/ps are 3 assuming A, B, C. Therefore, its equivalent Sop form: 4(A,B,C) -3 m (1,3) 10.30 mayo Pc

17.00 As the Pos equation have more no of olp than the Sop equation; hence, pos would generate low Complexity oki. The Corresponding ckt. is shown below, k map for Pos form. 12.30 А 6+ O+I 1+0 A 1 300 1 ( DO NCH 00 30 7- MOT A (B+C) 5) 4 = bem 2m (0,1, 4,5,6,8,10,11,12,13,14,15,16,17,18,19,20,21, 24,26,27,28,30, 31) this function is in Sop Form (as Im is given). The ho. of /ps are 5 Let us assume that A, B, C, DF E are the /ps. its equivalent Pos from, F = HTM(2,3,7,9,23,25,29) As the no. of o/p for sop is greater than Pos hence; Sop would generate low complexity ckt. As the no. of ilp is 5; the no. of k map would be 2; the Corresponding K-maps are given below, K map for A=0. (0-15) for A21 (16 31 0 Kmap DE BC 00 01 11 ot lo 1o 00 Oct - оо oji 01 o o o 10 o 101 4,-(DĒ + Be + BĐ + BD+CĒJĀ 42 - ADĒ + Be + BD+BD

00 thers; 4-7,+92 - ĀDĒ + ĀBC+Ā BD +Ā BD+ĀCĒ + A DĒ + ABC + AB 6+ ABD DE (A+Ā) + B D (A+Ā) + BD (A+Ā)+ Ā(B+ 2) + ABC = DE + B D + BD + ĀBĒ) + ABC - the Corresponding chi is shown below; A B 7 o с D E