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How many joules are released when 1.70 mol of 239Pu decays if each nucleus releases 5.243 MeV? * 10 (select) J Enter your ans
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QAns. 8.599 x 10s is the energy released. Calculation 23 Imole contains 6.023 x 10 atoms of 2304 py which is equal to 6.023

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