Question

DESCRIPTION:

You will be given a 1-D array, called wordFun, of Strings. The array has an unknown number of cells filled with data. As before, the array will already be filled with strings, some of which contain the string "Angela".

You will create a method called countItUp which returns and integer array containing the number of times each of the letters in my name occur within the strings within this array.

For example, if the input array was

wordFun = {"A", "Angela", "B", "gill", "e", "e"}

Counts would be:

A: 2
n: 1
g: 2
e: 3
l: 3
a: 1

thus the method countItUp would return the integer array {2, 1, 2, 3 ,3, 1}.

INPUT:

All input has been handled for you:

• A filled 1-D string array called wordFun
  

METHOD PROCESSING:

Use loops, arrays, and print statements to complete a new method called countItUp . This method should do the following:

• Read the wordFun array without altering its data
• Iterate through the wordFun array using a for loop
  • For each string in the array, loop through the letters and determine if any are one of those in my name ('A', 'n', 'g', 'e', 'l', or 'a')
    • Keep a count of the number of occurrences of each of those letters, incrementing every time you see another one.

METHOD RETURN VALUE:

• Once the the counts have been completed, the method would return those counts as an integer array of the form:
  
  { COUNT_OF_A, COUNT_OF_n, COUNT_OF_g, COUNT_OF_e, COUNT_OF_l, COUNT_OF_a}

NOTE: Only complete the countItUp method. Do not alter any other code.

Sample input/output:

Method argument	Method Return Value
{"A", "Angela", "B", "gill", "e", "e"}	{ 2, 1, 2, 3, 3, 1}
{"Angela", "Bill", "apple", "pear"}	{ 1, 1, 1, 3, 4, 3}

code:

import java.util.Scanner;

/**
* @author Angela Siegel
* @date 07/17/2020
*/

public class Question3 {

/**
* countItUp method
*/

   /*=====================================
   || DO NOT ALTER CODE BELOW THIS LINE ||
   =====================================*/

public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String[] words = in.nextLine().split(" ");

char[] letters = {'A','n','g','e','l','a'};
int[] counts = countItUp(words);
  
for (int i=0; i<6; i++) {
System.out.println(letters[i] + ": " + counts[i]);
}
}
}

Answer 1

Please comment if you have any doubt

Code:

import java.util.Scanner;
/**
* @author Angela Siegel
* @date 07/17/2020
*/
public class Question3 {
   /**
   * countItUp method
   */
   public static int[] countItUp(String wordFun[]){
       //array will store the count of letters
       int arr[]=new int[6];
       //iterate through the array
       for(int i=0;i<wordFun.length;i++){
           //iterate through the string
           for(int j=0;j<wordFun[i].length();j++){
               //if the letter is found
               //then corresponding place value will be incremented
               if(wordFun[i].charAt(j)=='A')
                   arr[0]+=1;
               else if(wordFun[i].charAt(j)=='n')
                   arr[1]+=1;
               else if(wordFun[i].charAt(j)=='g')
                   arr[2]+=1;
               else if(wordFun[i].charAt(j)=='e')
                   arr[3]+=1;
               else if(wordFun[i].charAt(j)=='l')
                   arr[4]+=1;
               else if(wordFun[i].charAt(j)=='a')
                   arr[5]+=1;
           }
       }
       //returning the array
       return arr;
   }
   /*=====================================
   || DO NOT ALTER CODE BELOW THIS LINE ||
   =====================================*/

   public static void main(String[] args) {
       Scanner in = new Scanner(System.in);
       String[] words = in.nextLine().split(" ");

       char[] letters = {'A','n','g','e','l','a'};
       int[] counts = countItUp(words);
      
       for (int i=0; i<6; i++) {
           System.out.println(letters[i] + ": " + counts[i]);
       }
   }
}

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | 25 26 | 27 28 import java.util.Scanner; /** * @author Angela Siegel * @date 07/17/2020 */ public class Question3 { /** * countItUp method */ public static int[] countItUp(String wordFun[]){ //array will store the count of letters int arr[]=new int[6]; //iterate through the array for(int i=0;i<wordFun.length;i++){ //iterate through the string for(int j=0;j<wordFun[i].length();j++){ //if the letter is found //then corresponding place value will be incremented if(wordFun[i].charAt(j)=='A') arr[@]+=1; else if(wordFun[i].charAt(j)=='n') arr[1]+=1; else if(wordFun[i].charAt(j)=='g') arr[2]+=1; else if(wordFun[i].charAt(j)=='e') arr[3]+=1; else if(wordFun[i].charAt(j)=='1') arr[4]+=1; else if(wordFun[i].charAt(j)=='a') arr[5]+=1; 29 ہ 30 31 32 33 34 35 36 37 38 //returning the array return arr; ہ || DO NOT ALTER CODE BELOW THIS LINE || ===*/

public static void main(String[] args) { Scanner in = new Scanner(System.in); String[] words = in.nextLine().split(" "); 39 40 41 42 43 44 45 46 47 48 49 50 char[] letters = {'A','n','g', 'e', 'l', 'a'}; int[] counts = countItUp(words); for (int i=0; i<6; i++) { System.out.println(letters[i] + } " + counts[i]); w 51 }

Output:

C:\Users\aravi\Desktop>java Question3 A Angela B gill e e A: 2 n: 1 g: 2 e: 3 1: 3 a: 1