x = 12.83
s = 2.19
(a) t-critical value = 1.76
= x ± t*(s/√n)
= 12.83 ± 1.76*(2.19/√15)
= 11.8307, 13.8226
(b) We are 90% confident that the population mean diameter of bearings is between 11.8307 and 13.8226.
(c) The hypothesis being tested is:
H0: µ = 14
Ha: µ ≠ 14
The test statistic, t = (x - µ)/s/√n
t = (12.83 - 14)/2.19/√15 = -2.075
The critical value is 2.145.
Since 2.075 > 2.145, we fail to reject the null hypothesis.
Therefore, we cannot conclude that µ ≠ 14.
(d) The hypothesis being tested is:
H0: µ = 14
Ha: µ < 14
The test statistic, t = (x - µ)/s/√n
t = (12.83 - 14)/2.19/√15 = -2.075
The p-value is 0.0285.
Since the p-value (0.0285) is less than the significance level (0.10), we can reject the null hypothesis.
Therefore, we can conclude that µ < 14.
(e) Since 14 is above the confidence interval's upper limit, we can say that µ < 14.
(f) We cannot conclude that µ = 14.
An engineer measured the diameter of bearings in cm. 10.2 16.9 13.3 12.5 12.1 10.0 10.9...
An engineer measured the diameter of bearings in cm. 10.2 16.9 13.3 12.5 12.1 10.0 10.9 13.5 16.6 11.1 12.0 16.2 12.3 11.8 13.0 It is believed that the diameters of bearings form a normal distribution. Find an efficient interval that 90% of the data would lie. Find an efficient interval that the population mean diameter of bearings would lie with 90% confidence. Test whether the population mean diameter of bearings is 14 at α =0.05 by the critical value...
photos for each question are all in a row
(1 point) In the following questions, use the normal distribution to find a confidence interval for a difference in proportions pu - P2 given the relevant sample results. Give the best point estimate for p. - P2, the margin of error, and the confidence interval. Assume the results come from random samples. Give your answers to 4 decimal places. 300. Use 1. A 80% interval for pı - P2 given that...