Question

You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly more than 0.68. You use a significance level of a = 0.002. Ho:p=0.68 H:p > 0.68 You obtain a sample of size n = 359 in which there are 253 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic - What is the p-value for this sample? (Report answer accurate to four decimal places.) P-value The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null fail to reject the null

Answer 1

Given,

$p = \frac{253}{359} = 0.7047$

We know that,

$Z = \frac{p - p_{0}} {\sqrt{\frac {p_{0}(1 - p_{0})} {n}}}$

$Z = \frac{0.7047 - 0.68} {\sqrt{\frac {0.68(1 - 0.68)} {359}}}$

Therfore, the test statistic is,

Test statistic = 1.003

P value = 0.1579

The p value is,

greater than a

The test statistic leads a decision to,

Fail to Reject the null

The final conclusion is that,

There is not sufficient sample evidence to support the claim that the proportion of women over 40 who regularly have mammogram is more than 68