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Consider the circuit shown below. 5Ω 4A R 8 ξ10 Ω 4 Ω ν 240V 10 ΩΣ ξ14 Ω 6 Ω a- (10 pts) Find R. b- (10 pts) Find the total p

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ISR 4A ce an kulapply at loop 10 2012 here loop current 1224 R 240 -240 +, -12) R +0,- 3)10 =0 i, Clo+R) -1012 = 140+4R. - atFrau =) 4R-PR 5-76 +41) 4R – 29R = 76+469) -25R =-40 R = log2 = total paver delbered to thee Corcuit by 240 voltsource P240 =

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