Ans 22)
ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under equilibrium conditions, Q=K (equilibirium constant) and ΔG=0 so ΔG0=−RTlnK = -(8. 314 j/mol.K)(300K) (ln 2.5*10^3) = -19514. 7 j/mol = -19.5 kj/mol.
Ans 23
As heterogeneous name refer different
In heterogeneous catalysis, catalyst and reactants are in different phase.
Ans 24)
If reaction quioent is less than Kc
The equilibrium must move in a forward direction and to produce more products
Explanation:
For the reaction,
A+B⇌C+D,
we write Kc=[C][D]/[A][B]
This describes an equilibrium condition, where the rate of forward reaction is equal to the reverse rate of reaction.
Under non-equilibrium conditions, (for instance at the start of the reaction), we write Q(rxn quotient) =[C][D]/[A][B].
At the start of the reaction, we can conceive that the reactant concentrations, [A] and [B], are LARGER than they would be at equilibrium, so Qrxn < Kc,and so the reaction proceeds in a forward direction, until Qrxn = Kc.
22. A process has an equilibrium constant K of 2.5 x 10' at 300 K. What...
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