At ti = 4.00 s, the acceleration of a particle moving at constant speed in counterclockwise...

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Question

At ti = 4.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is a = (4.00m/s2)

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Answer 1

Answer #1

a = 4 at t = 48 8 ê - 4 at t = 68 product of a and az is zero aaq = 0 Tag 2 Dot so, a, and a perpendicular Given moves counte

Answer 2

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