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Question 46 Type your calculations for possible partial credit. Your answer also needs to of significant figures. Given [H3O+
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Question 46: Solution : ko [thot] [ou Ix 10 -14 [ou] = 1x1014 [Hot] 1 x 0 -14 1.9x108 [on] = -6 = 0.5263x10 ºm Cross-check: pConcentration of or ions = lopo . 80.9- 01 = = 5.2E-7 = 0.52x106m -

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