Heat is provided only during the process from B to C, because here volume increases and the process is non-adiabatic.
Therefore, heat provided =
.
Now, work done in the process from A to B =
[since A to B is an adiabatic process]
Work done in the process from B to C =
[since B to C is an isobaric process]
Work done in the process from C to D =
[since C to D is an adiabatic process]
Work done in the process from D to A = 0 [since D to A is an isochoric process].
Therefore, total work done =


Now, efficiency = Total work done / heat provided





.
[Hence proved]
An idealized diesel engine operates in a cycle known as the air-standard diesel cycle shown in...
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Problem 8: Consider the reversible Carnot's cycle of an ideal monatomic gas in the cold cylinder of 290 K corresponding to the isothermal compression step. Then the volume of the gas is further compressed by a factor of 7.5 in the adiabatic compression step. a) Find the temperature at the final step of the adiabatic compression. b) What is Thot for the isothermal expansion step? c) What is the maximum thermodynamic efficiency for this engine? d) How much would the...
A Diesel engine is approximated by a pressure limited (dual)
cycle. The data is as follows:
A Diesel engine is approximated by a pressure limited (dual) cycle. The data is as follows: Inlet temperature and pressure: P1 = 100 kPa, T1 = 298 K Compression ratio = 16:1 Heat added during combustion = 44000 kJ/kgfuel (please note that this value is per kg fuel) A/F = 23 kg/kgf 40% of the heat is added in the constant volume combustion part....
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