Question

7) (3 points) Use current division to find the current Ix below: Ix = w 10 Ix 30 30 24 mA 20 8) (3 points) Use current division to find the current Ix below: Ix = 10 20 IX 20 30 40 24 mA

PLEASE SHOW ALL WORK AND BOX THE ANSWERS

Answer 1

R Is. + R YAR vo R3 UR u network be Comes. Sol current division rule. IR Is IR= VIR Voltage division rule VRE Vs. The given circuit is. w 20 let's first calculate Vai network. By simplifying Go =) 30 -> 20 lotzet20260 BoxGo pro 30tGo 10 30 the using voltage division Ture. lo + 30 Va 330 Isov Voc 20 I 20 30 M mm 20 given 20 va - 20 * 150 20110120 SO 20 FASO GOV SVA

Going back original network. t 30 30 va VX ISOV we know va this time. so taking va as soure applying voltage division M 20 20 Yule 30 Vc= x60 Botlo+20 So, Ixc=30V 30x60 = 30V/ Go 7) The giver circuit is. 3 330 Sx w 20 In series connection, the current would be same throug all resistors. simplifying the network. Į 60 30 24mA Ix using current division rule. 3o x 24. Ia Go+30 30 x 24 ASSA Ix = 8mA

8 The given circuit is M 10 w w 40 30. 20 24mA Ix simplifying the network. 2otto = Go WW 30 Qama Go 30 M Ix. 30x30 Bot30 24mA 30x30 Go 15 = Ix =15 using the current division rule. 15 X24. Ix = is+GO B ] x24. IS Ix=4.8 mA