Question

Help please and circle the answer and make it clear and visible, thanks. Ive also included a similar problem so you know what the answer to the blank problem should look like

Suppose that the value of the Inventory at Fldo's Pet Supply decreases, or depreciates, with time t, in months, where Vis given by the formula to the right. a) Find VIO), V(5), V(20), and V(70). b) Find the maximum value of the inventory over the interval [0,00). c) Sketch a graph of V. d) Does there seem to be a value below which V(t) will never fall? Explain. Vſt) = 30- 15° (t+3)2 a) (O)=(Round to two decimal places as needed.) V(5)=(Round to two decimal places as needed.) V(20) = (Round to two decimal places as needed.) V[70) - (Round to two decimal places as needed.) b) The maximum value of Vit) over the interval [0.c.) is. c) Choose the correct graph below. OA Ов. Ос. 401 404 20 401 1541 d) Does there seem to be a value below which V(t) will never fall?

Answer 1

soll V (t) 30 15 t² (t+3) 2 0 9) vlo) 30 24:14 v(s= 30 -15 (542 ( 15/20/? v (30) 18.66 = 30- (23)? V (70) 30 16-21 - 15(70) (73)2 3o maximum value b ) valued VE) c) goroph (0,3) С option yt A d) option from VY graph Yes, the largest value "(t) will never fall is is. This is horizontal aym tote at (y=15) - because the group he of below has

2 vet) 70 – 35+ At+3) 2 a ) Vlo) = 70 M(s) 56.33 v (30) = 41.07 v (70) = 37.82 maximumum Valuu 7o y ucts 70 ) graph option B 35 t D d) Yes lopton D the largest value r(t) will nerey below io 35. This is because the graph horizon fal asymtote. fall a 30 Vat has